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Hide the output of echo json_encode

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[前端(javascript) 所属分类 前端(javascript) | 发布者 店小二03 | 时间 2019 | 作者 红领巾 ] 0人收藏点击收藏

I was passing an array inphp to javascript using json_encode and ajax. It seems that the only way is to use

echo json_encode($var)

which also prints out the information of $var on the page because of echo. Is there an easy way to hide the output? My code was like the follows,

main.php

<?php include_once('testing.php'); ?> <!DOCTYPE html> <html> <head> <title></title> </head> <body> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script> <script type="text/javascript" src="testing.js"></script> </body> <html>

testing.php

<?php $var=array('1','2','3','4','5'); echo json_encode($var); ?>

testing.js

$.ajax({ url : './testing.php', type : "GET", dataType : 'json', success : function (result) { showstaff(result); } }); function showstaff(x){ console.log(x); }

Running main.php print out the array('1','2','3','4','5') on the page and show the array in the console, but what I need is to just show the array in the console (i.e. hide the results from the page).

You don't need include_once('testing.php') in main.php . When main.php is sent to the browser, it will load testing.js , which will then execute testing.php via the AJAX call.

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