all. I am trying to learn Laravel and I am working on uploading an image. I get the following error:

"Call to a member function getClientOriginalName() on a non-object"

I am using these packages:

"anahkiasen/former": "dev-master", "intervention/image": "dev-master", "intervention/imagecache": "2.*"

After using SO, I have verified the following are NOT contributing to the error above:

multipart/form-data on form Upload file data exists Thephp.ini max_filesize is way larger than the size of this small test file

My form is:

<form enctype="multipart/form-data" accept-charset="utf-8" class="form-horizontal" id="create_form" method="POST" action="/elements"> <div class="control-group"><label for="img[]" class="control-label">Upload Image</label><div class="controls"><input multiple="true" class="myclass" accept="image/gif|image/jpeg|image/png" id="img[]" type="file" name="img[]"></div></div> <div class="form-actions"><input class="btn-large btn-primary btn" type="submit" value="Submit"> <input class="btn-large btn-inverse btn" type="reset" value="Reset"></div> <input type="hidden" name="_token" value="B0AJ0Y5LMrMng6CsePeZfNSvRQ0KexowOGTK99Gm"> </form>

The code to generate the error is:

$image = Input::file('img'); $filename = $image->getClientOriginalName(); print_($filename);

If I print out the object using:

print_r($image);

...then I get:

Array ( [0] => Symfony\Component\HttpFoundation\File\UploadedFile Object ( [test:Symfony\Component\HttpFoundation\File\UploadedFile:private] => [originalName:Symfony\Component\HttpFoundation\File\UploadedFile:private] => storageunit.jpg [mimeType:Symfony\Component\HttpFoundation\File\UploadedFile:private] => image/jpeg [size:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 8734 [error:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 0 [pathName:SplFileInfo:private] => /tmp/php9AU1OE [fileName:SplFileInfo:private] => php9AU1OE ) )

All of which looks correct to me, so I am stumped.

If anyone has any ideas as to what to try next, I would appreciate the help.

Look at what's printed out. $image is an array of objects, not an object. Try:

$filename = $image[0]->getClientOriginalName();

本文开发(php)相关术语:php代码审计工具 php开发工程师 移动开发者大会 移动互联网开发 web开发工程师 软件开发流程 软件开发工程师

分页:12
转载请注明
本文标题:Laravel &amp; ldquo&amp;semi; File Upload Error Invoke a member function get ...
本站链接:https://www.codesec.net/view/628117.html


1.凡CodeSecTeam转载的文章,均出自其它媒体或其他官网介绍,目的在于传递更多的信息,并不代表本站赞同其观点和其真实性负责;
2.转载的文章仅代表原创作者观点,与本站无关。其原创性以及文中陈述文字和内容未经本站证实,本站对该文以及其中全部或者部分内容、文字的真实性、完整性、及时性,不作出任何保证或承若;
3.如本站转载稿涉及版权等问题,请作者及时联系本站,我们会及时处理。
登录后可拥有收藏文章、关注作者等权限...
技术大类 技术大类 | 开发(php) | 评论(0) | 阅读(34)