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Filtering each object with an equal value in individual arrays

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[前端(javascript) 所属分类 前端(javascript) | 发布者 店小二04 | 时间 2019 | 作者 红领巾 ] 0人收藏点击收藏

I'll just cut straight to the chase.

Let's say I have a simple array of objects, where some objects' dates are equal:

[{value: 67, date: 91}, {value: 48, date: 91}, {value: 15, date: 92}, {value: 77, date: 92}, {value: 10, date: 93}, {value: 5, date: 93}]

How can I filter the array so that objects with equal dates return in their own individual arrays like this:

[{value: 67, date: 91}, {value: 48, date: 91}] [{value: 15, date: 92}, {value: 77, date: 92}] [{value: 10, date: 93}, {value: 5, date: 93}]

How about using array.reduce()

var array = [{value: 67, date: 91}, {value: 48, date: 91}, {value: 15, date: 92}, {value: 77, date: 92}, {value: 10, date: 93}, {value: 5, date: 93}]; filteredArray = array.reduce((pre,curr)=> { // check if the object has unqiue date as key if(!pre.hasOwnProperty(curr['date'])){ // if not, create an array with the unique date as key pre[curr['date']] = []; } //push current value to array based on date pre[curr['date']].push(curr); // return the object return pre; }, {}); console.log(filteredArray); console.log(Object.keys(filteredArray)); var asArray = Object.keys(filteredArray).reduce((pre,curr)=>{pre.push(filteredArray[curr]); return pre},[]) console.log(asArray);

For notes, refer to comments.

EDIT: This way you can easily get the unique dates. By doing Object.keys(filteredArray) or extract the arrays by just doing asArray = Object.keys(filteredArray).reduce(e)=>{prev.push(filteredArray[e]); return pre},[]}

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