未加星标

Find files with more than one match using grep

字体大小 | |
[系统(linux) 所属分类 系统(linux) | 发布者 店小二04 | 时间 2018 | 作者 红领巾 ] 0人收藏点击收藏

I'm wondering if there's a way to list files with more than 1 match using grep. Here's what i'm doing. I'm trying to go through a client's website and replace the last match with a string. so at the bottom of every page, he has this line:

<p align="center"><font face="Arial" color="#808080" size="2">

which is followed by a footer. I need to replace it (using sed) with this line:

<php include 'footer.php'; ?>

but i want to isolate the files that only have 1 instance of that first line, so i can replace them. Another solution to my problem would be to use sed on only the last match, or use sed on the last 50 lines of a file. any ideas for me?

You can actually use grep -c to get a count of matches in a file:

grep -c '<p align="center"><font face="Arial" color="#808080" size="2">' file

To store its output

cnt=$(grep -c '<p align="center"><font face="Arial" color="#808080" size="2">' file)

本文系统(linux)相关术语:linux系统 鸟哥的linux私房菜 linux命令大全 linux操作系统

代码区博客精选文章
分页:12
转载请注明
本文标题:Find files with more than one match using grep
本站链接:https://www.codesec.net/view/611145.html


1.凡CodeSecTeam转载的文章,均出自其它媒体或其他官网介绍,目的在于传递更多的信息,并不代表本站赞同其观点和其真实性负责;
2.转载的文章仅代表原创作者观点,与本站无关。其原创性以及文中陈述文字和内容未经本站证实,本站对该文以及其中全部或者部分内容、文字的真实性、完整性、及时性,不作出任何保证或承若;
3.如本站转载稿涉及版权等问题,请作者及时联系本站,我们会及时处理。
登录后可拥有收藏文章、关注作者等权限...
技术大类 技术大类 | 系统(linux) | 评论(0) | 阅读(59)